Max Force & Acceleration on 0.466 kg Mass w/ 144 N/m Spring

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The discussion focuses on calculating the maximum force and acceleration of a 0.466 kg mass attached to a spring with a spring constant of 144 N/m, released from a compressed position of 0.174 m. The maximum force is determined using Hooke's Law, resulting in a value of 25.056 N. To find the maximum acceleration, the formula F = ma can be applied, where the known force and mass are used to calculate acceleration. The user expresses confusion about deriving the maximum acceleration from the known values. The conversation emphasizes the relationship between force, mass, and acceleration in the context of spring dynamics.
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a 0.466 kg mass is attached to a spring with a spring constant 144 N/m so that the mass is allowed to move on a horizontal frictionless surface. The mass is released from rest when the spring is compressed 0.174 m. what is the maximum force on the mass and the maximum acceleration?

i used the eq. Force of the Spring = -(k)(x) to get the force on the mass
 
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I think all you need is F = ma = -kx

You might also use W = F*d = mad = -kx^2d/2
 
thats what i did to get the force, and i got 25.056 N, i am confused of to how i would get the max acceleration
 
You know the force, you know the mass. Find A
 
oh yeah, thanx
 
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