Net Forces and Tension Practice Problems

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The discussion focuses on solving tension problems involving multiple boxes with varying masses. The user is struggling with problem 6, particularly with the net forces acting on a 2M box, questioning whether to include its weight in the calculations. It is confirmed that the weight should always be included in free body diagrams, and the user is guided to correct their equations for the 2M block. After substituting equations and solving, the user arrives at an acceleration of 7 m/s², but believes the correct answer is actually 8.6 m/s², indicating potential discrepancies in the provided solutions. The conversation emphasizes the importance of accurately representing forces in tension problems for correct outcomes.
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I'm trying to improve on tension problems so I am practicing using this website: http://www.education.com/study-help/article/tension/

I am on problem 6, but I keep coming up with the wrong answers. I attempted this by trying to show the net forces for each box.

Box M net forces
T upwards
Mg downwards
F = T - Mg = Ma

Box 2M net forces
T upwards
T' downwards
***should I include the weight (2Mg) of this box?

Box 4M net forces
4Mg downwards
T' upwards
F = 4Mg - T' = 4Ma

I have a feeling there is an error in box 2M that is fudging with my results. Lastly, does T = 6Mg? Help?? :confused:
 
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bulbasaur88 said:
I'm trying to improve on tension problems so I am practicing using this website: http://www.education.com/study-help/article/tension/

I am on problem 6, but I keep coming up with the wrong answers. I attempted this by trying to show the net forces for each box.

Box M net forces
T upwards
Mg downwards
F = T - Mg = Ma
yes
Box 2M net forces
T upwards
T' downwards
***should I include the weight (2Mg) of this box?
always include the weight in any free body diagram
Box 4M net forces
4Mg downwards
T' upwards
F = 4Mg - T' = 4Ma
yes
I have a feeling there is an error in box 2M that is fudging with my results. Lastly, does T = 6Mg? Help?? :confused:
yes, correct your error for the net forces acting in the FBD of the 2M block.
 
was my error that I didn't include the weight? or is it another entirely separate error in block 2m?
 
Is the equation for block 2m:

F = 2Mg + T' - T = 2Ma?
 
bulbasaur88 said:
Is the equation for block 2m:

F = 2Mg + T' - T = 2Ma?
yes. Now solve for T, T', and a. (Note: T is not equal to 6Mg)
 
I solved it and it still incorrect.

Block M
T - mg = ma <---plug in m = 1 Kg
T - 9.8 = a
T = 9.8 + a equation 1

Block 2M
T' + 2mg - T = 2ma <---Plug in m = 1 kg
T' + 2(9.8) - T = 2a
T' + 19.6 - T = 2a equation 2

Block 4M
4mg - T' = 4ma < --- plug in m = 1 kg
4(9.8) - T' = 4a
T' = 39.2 - 4a equation 3

Substitute equation 1 and equation 3 into equation 2
equation 2: T' + 19.6 - T = 2a
(39.2 - 4a) + 19.6 - (9.8 + a) = 2a
Solve for a.

a = 7 m/s^2

Correction answer is 8.6 m/s^2.
 
We were correct :D

The answer provided is incorrect I believe. Someone solved it out and got the same answer as I did here, http://www.myteacherpages.com/webpages/niedzielam/files/AP%20Review%2001%20Tension%20SOLUTIONS.pdf .
 
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Thank you phanthomjay *air hug*
 
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