What the heck is meant by Pauli force/effect ?

  • Thread starter Thread starter nonequilibrium
  • Start date Start date
  • Tags Tags
    Pauli
nonequilibrium
Messages
1,412
Reaction score
2
What the heck is meant by "Pauli force/effect"?

I'm a last year physics undergrad and whenever I have a physics class given by an experimental physicist (e.g. solid state physics), they sometimes say things like "... and because of the Pauli force these two electrons are repelled ..." and whenever I enquire about what is meant, I get an answer like "it's due to the Pauli exclusion principle".

But the latter only states that two fermions cannot be in exactly the same state; it says nothing about a repulsive force that acts on two fermions close to each other. In essence the Pauli exclusion principle does nothing to prevent two fermions in being arbitrarily similar states, as long as the states are not exactly the same.

So what is the deal: is there an actual Pauli force additional to the Pauli exclusion principle (NB: let's not get into a semantic discussion about the word "force", call it what you will, I'm simply referring to the so-called repulsive effect of two fermions close to each other)? Or are my experimental physicis professors botching the concept of Pauli exclusion principle, making their arguments using it fallacious (i.e. there is only the Pauli exclusion principle, no repulsive effect)?
 
Physics news on Phys.org


mr. vodka said:
I'm a last year physics undergrad and whenever I have a physics class given by an experimental physicist (e.g. solid state physics), they sometimes say things like "... and because of the Pauli force these two electrons are repelled ..." and whenever I enquire about what is meant, I get an answer like "it's due to the Pauli exclusion principle".

But the latter only states that two fermions cannot be in exactly the same state; it says nothing about a repulsive force that acts on two fermions close to each other. In essence the Pauli exclusion principle does nothing to prevent two fermions in being arbitrarily similar states, as long as the states are not exactly the same.

So what is the deal: is there an actual Pauli force additional to the Pauli exclusion principle (NB: let's not get into a semantic discussion about the word "force", call it what you will, I'm simply referring to the so-called repulsive effect of two fermions close to each other)? Or are my experimental physicis professors botching the concept of Pauli exclusion principle, making their arguments using it fallacious (i.e. there is only the Pauli exclusion principle, no repulsive effect)?

You're perfectly right, your professor used the Pauli exclusion principle in a wrong way.
I think it's common in solid state physics to do the same error, I've read the same thing in the Ashcroft and Mermin book to justify the Lennard-Jones potential repulsive term.

Pauli principle states that the state of a system of fermions is anti-symmetric in the excange of two fermions.
It can be interpret with a effective force when, for example, you use the Hartree-Fock approximation. In doing this you find that the anti-symmetry of the wave function acts as an additiona term in the Hamiltonian, the "excange energy". This energy is though not necessarily positive, for example in the "jellium" model you find its effect is actractive. The specific form of this energy depends on both the interaction and the wavefunction you're using as an approximation.

In conclusion it's right to think about the Pauli principle as an effective energy in some approximation, but you can't know a priori if it's an actractive or a repulsive contribution.

Ilm
 
Last edited:


I see, interesting... Do you know of a source that addresses this issue, i.e. that mentions the common fallacious reformulations and in what ways it is correct (apparently related to the Hartree-Fock approximation)?
 


mr. vodka said:
I see, interesting... Do you know of a source that addresses this issue, i.e. that mentions the common fallacious reformulations and in what ways it is correct (apparently related to the Hartree-Fock approximation)?
I don't know where to find a general treatment of this issue.

You can simply try to find something on the excange energy and then constate it can be both positive or negative, maybe checking this explicitly in different examples.

For a simple treatment of Hartree-Fock approximation you can read almost every solid state physics book (check it on physics forum), even Ashcroft, Mermin, Solid State Physics (I personally hated this book :mad:).
You can certainly find some example here where anti-symmetry of the state produce a positive term in the energy of the system.
Only believe in what is demonstrated though :smile:

For a rigorous treatment (but not so easy) of Hartree-Fock approximation look for books on many-body quantum physics like Fetter, Walecka, Quantum Theory of Many-Particle Systems.
Here you can find even the very simple example of the jellium model (not using Hartree-Fock if I remember it right), where anti-symmetry of the state produce a negative term in the mean energy of the system.

edit: to avoid misunderstanding, to my knowledge treating anti-symmetry of fermions states as an effective potential is not strictly related to Hartree-Fock, which is only one of the possible approximations resulting in such a term in the Hamiltonian.

Ilm
 
Last edited:


This question has in fact been asked a couple of times before on PF, for example by myself a year or two ago, see here:

https://www.physicsforums.com/showthread.php?t=409034

The discussion gets a bit off-topic after a while, but you should at least read through the first pages.

It is clear from that discussion what the standard explanation for this issue is, but I'm not so sure that it explains it fully for me (yet, maybe it's only a matter of thinking it through/working through math).
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
Not an expert in QM. AFAIK, Schrödinger's equation is quite different from the classical wave equation. The former is an equation for the dynamics of the state of a (quantum?) system, the latter is an equation for the dynamics of a (classical) degree of freedom. As a matter of fact, Schrödinger's equation is first order in time derivatives, while the classical wave equation is second order. But, AFAIK, Schrödinger's equation is a wave equation; only its interpretation makes it non-classical...
I am reading WHAT IS A QUANTUM FIELD THEORY?" A First Introduction for Mathematicians. The author states (2.4 Finite versus Continuous Models) that the use of continuity causes the infinities in QFT: 'Mathematicians are trained to think of physical space as R3. But our continuous model of physical space as R3 is of course an idealization, both at the scale of the very large and at the scale of the very small. This idealization has proved to be very powerful, but in the case of Quantum...

Similar threads

Replies
17
Views
3K
Replies
12
Views
2K
Replies
2
Views
2K
Replies
3
Views
1K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
6
Views
3K
Back
Top