SwordSmith
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I am not sure what the derivative with respect to a complex conjugate is and I have not been able to find it in any books.
I assume I should use the chain rule somehow to figure this out:
\frac{\partial z}{\partial z^*}, \quad z=x+iy
Maybe you can do like this?
\frac{\partial z}{\partial z^*}=\frac{\partial z}{\partial x} \frac{\partial x}{\partial z^*}+\frac{\partial z}{\partial y}\frac{\partial y}{\partial z^*}
\quad \quad = 1\cdot\frac{\partial x}{\partial (x-iy)} + i\cdot\frac{\partial y}{\partial (x-iy)}
\quad \quad = 1 + i\cdot\frac{-1}{i} =0
I am not sure the above procedure is correct. Can someone in here confirm the result or, if not, help me?
I assume I should use the chain rule somehow to figure this out:
\frac{\partial z}{\partial z^*}, \quad z=x+iy
Maybe you can do like this?
\frac{\partial z}{\partial z^*}=\frac{\partial z}{\partial x} \frac{\partial x}{\partial z^*}+\frac{\partial z}{\partial y}\frac{\partial y}{\partial z^*}
\quad \quad = 1\cdot\frac{\partial x}{\partial (x-iy)} + i\cdot\frac{\partial y}{\partial (x-iy)}
\quad \quad = 1 + i\cdot\frac{-1}{i} =0
I am not sure the above procedure is correct. Can someone in here confirm the result or, if not, help me?