ktsharp
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Hi Everyone,
I am trying to solve a system of non-linear differential equations coupled to algebraic expressions:
W(x)' = f(Cn(x)), where n = 1:6
C1(x)' = f(Cn(x),V1(x),V2(x))
C2(x)' = f(Cn(x),V1(x),V2(x)),
C3(x)' = f(Cn(x),V1(x),V2(x)),
V1(x)'' = f(Cn(x),V1(x),V2(x)),
0 = gm(Cn(x),V1(x),V2(x)), where m = 1:4
I am trying to use Matlab's inbuilt decic.m function to calculate consistent initial conditions for each variable that will satisfy the system. I am splitting up the equation for V1(x)'' into two first order ODEs, and will declare V1(X)' as a variable. This makes a system of ten equations in total.
Decic takes two vectors which estimate the initial value of each variable and it's derivative. I would like to choose the initial values for W(0), C1(0), C2(0), C3(0) and V1(0). This I believe means they become fixed when passing them into the decic function. The rest of the values can be anything reasonable that is consistent with the system of equations.
The problem I have with Matlab is that the error I am receiving tells me to free up fixed components. I end up freeing all of them, i.e. fixed_yo = zeros(1,10) and fixed_yp0 = zeros(1,10) and I still receive the error telling me to free up 1 fixed component. I have no more components to free. What does this mean? How do I get around this issue, and/or is there an alternative method I could use to find consistent initial conditions?
Thanks so much for any helpful feedback, please ask any questions that may help.
kt
I am trying to solve a system of non-linear differential equations coupled to algebraic expressions:
W(x)' = f(Cn(x)), where n = 1:6
C1(x)' = f(Cn(x),V1(x),V2(x))
C2(x)' = f(Cn(x),V1(x),V2(x)),
C3(x)' = f(Cn(x),V1(x),V2(x)),
V1(x)'' = f(Cn(x),V1(x),V2(x)),
0 = gm(Cn(x),V1(x),V2(x)), where m = 1:4
I am trying to use Matlab's inbuilt decic.m function to calculate consistent initial conditions for each variable that will satisfy the system. I am splitting up the equation for V1(x)'' into two first order ODEs, and will declare V1(X)' as a variable. This makes a system of ten equations in total.
Decic takes two vectors which estimate the initial value of each variable and it's derivative. I would like to choose the initial values for W(0), C1(0), C2(0), C3(0) and V1(0). This I believe means they become fixed when passing them into the decic function. The rest of the values can be anything reasonable that is consistent with the system of equations.
The problem I have with Matlab is that the error I am receiving tells me to free up fixed components. I end up freeing all of them, i.e. fixed_yo = zeros(1,10) and fixed_yp0 = zeros(1,10) and I still receive the error telling me to free up 1 fixed component. I have no more components to free. What does this mean? How do I get around this issue, and/or is there an alternative method I could use to find consistent initial conditions?
Thanks so much for any helpful feedback, please ask any questions that may help.
kt