Calculate K_C for N2, H2 System: 10.7M^2, 4.00M^2, 2.67M^2, 1.67M^2

AI Thread Summary
To calculate the equilibrium constant K_C for the N2 and H2 system, the balanced chemical equation is essential, specifically the Haber process: N2 + 3H2 ⇌ 2NH3. Given initial concentrations of N2 at 0.32M and H2 at 0.66M, and an equilibrium concentration of H2 at 0.30M, the change in concentration for H2 is determined. The stoichiometry of the reaction indicates that for every 3 moles of H2 consumed, 1 mole of N2 is consumed, affecting the equilibrium concentrations of both gases. After calculating the equilibrium concentrations and substituting them into the K_C expression, the correct value can be determined from the options provided. The final result will yield the equilibrium constant for the reaction.
ultimateguy
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Homework Statement


N_{2(g)}, 0.32M and H_{2(g)}, 0.66M are placed in a reaction vessel. The system reaches equilibrium when [H_{2(g)}] = 0.30M. Calculate K_C

a) 10.7M^2
b) 4.00M^2
c) 2.67M^2
d) 1.67M^2

Homework Equations


Equilibrium constant formula

The Attempt at a Solution


This is just messing me up because the chemical equation isn't given. If I don't know the products, how do I get the equilibrium constant?
 
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i s'pose this is the famous haber's process eqn.
N2+3H2---->2NH3

(and this is reversible)
 
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