Does photon have upper limit energy ?

magnetar
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Does photon have upper limit energy ?

Does photon have upper limit energy(beyond gamma-ray) ?Thank you !
 
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mmm...not really sure... but perhaps the Planck scale is the ultimate (so far)... you may have problems if your photon wavelength is shorter than the Planck length or at least the rules of the game may change (?)
 
yes- Planck energy- a photon at Planck energy would have a wavelength equal to the Planck length-
 
magnetar said:
Does photon have upper limit energy(beyond gamma-ray) ?Thank you !
No. There is no upper limit.
The Planck energy is large, but is not a limit.
 
You may consider that a frequency higher than an inverse Planck time is not meaningful in current theories, so that we cannot give a clear meaning to a photon energy higher than 1/sqrt (hbar * G / c^5) * h.
 
In current QFT, which is at the origin of the concept of what is a "photon", there is no official upper limit on what is the maximal energy of a photon.
However, there are two caveats:
- the first is that gravity (which is NOT included in QFT as we know it), suggests that there will be trouble around the Planck energy. In other words, we think that whatever QFT might say about arbitrarily high energies, it will not be correct because gravity will not only be not neglegible (as it is assumed in QFT), but it will rather be so dominant that it is meaningless to try to work with a theory that doesn't contain gravity
- QFT itself, as we know it, has a serious problem at high energies. We think that current QFT are "low energy effective" approximations to something else, and this approach is what justifies renormalisation schemes. This has nothing to do with Planck scales, but rather with the intrinsic structure of QFT.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
Not an expert in QM. AFAIK, Schrödinger's equation is quite different from the classical wave equation. The former is an equation for the dynamics of the state of a (quantum?) system, the latter is an equation for the dynamics of a (classical) degree of freedom. As a matter of fact, Schrödinger's equation is first order in time derivatives, while the classical wave equation is second order. But, AFAIK, Schrödinger's equation is a wave equation; only its interpretation makes it non-classical...
Thread 'Lesser Green's function'
The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...
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