How Do You Calculate Tension and Compression in a Hanging Restaurant Sign?

AI Thread Summary
To calculate the tension and compression in a hanging restaurant sign, one must consider the forces acting on the system, including the weight of the sign and the angles involved. The sign, weighing 25 kg, is suspended from a horizontal pole and connected to a cable, creating a scenario where both tension in the cable and compression in the pole need to be determined. Utilizing the sine law may be a starting point, but understanding moments (torques) is crucial for solving the problem accurately. A diagram of the setup can aid in visualizing the forces at play. Proper analysis of these forces will lead to the correct calculations of tension and compression.
webspherev6
Messages
2
Reaction score
0

Homework Statement



a 25 kg restaurant sign hangs from a 1.25m horizontal pole with one end fastened at right angle to the brick wall of a restaurant and the other end fastened to a 2.5m cable . determine the force of compression actng on the pole and the tension in the cable.


Homework Equations



im totally clueless this is a past test question. i was thinking u could possible use the sin law

t1=t2sin(angle2)/sin(angle1) ?? this is where t is the tension. i would like help understanding how to calculate them.


Oh i drew the diagram so i know how it loks like

The Attempt at a Solution

 
Physics news on Phys.org
Try looking at moments (torques).
 

Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
View full post »

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
View full post »

Similar threads

Find the tension in the cable and reactive forces at ground
Replies
4
Views
5K
Vertically Stretched Spring w/ Hanging Mass.
Replies
1
Views
3K
How Do You Calculate Forces and Balance a Hanging Cafe Sign?
Replies
18
Views
3K
Calculating Tension and Net Force in Suspended Cable System
Replies
3
Views
3K
How Do You Calculate the Tension in a Wire Supporting a Sign?
Replies
8
Views
3K
How Is Tension Calculated in a Rope During Rock Climbing?
Replies
18
Views
9K
Hanging Chandelier (A question about Tension Force)
Replies
2
Views
27K
How Is the Vertical Force Calculated at the Hinge in a Beam and Sign System?
Replies
8
Views
6K
How do I calculate the tension in cable 1 without using the tension in cable 2?
Replies
2
Views
5K
What is the Force of Tension and Acceleration in a Hanging Mass System?
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top