What is the initial velocity of the ball thrown by Nicole?

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Nicole threw the ball straight up, and it passed Chad at a height of 5.0 meters with a speed of 10 m/s on its way down. To find the initial velocity, the equation v^2 = u^2 + 2as was used, where the downward speed at the same height was considered positive for upward motion. The acceleration due to gravity was taken as -9.8 m/s², and the height was set at 5 meters. The correct initial velocity calculated was 14 m/s. This demonstrates the application of kinematic equations in solving projectile motion problems.
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[SOLVED] How fast was the ball thrown?

Homework Statement



Nicole throws a ball straight up. Chad watches the ball from a window 5.0m above the point where Nicole released it. The ball passes Chad on the way up, and it has a speed of 10 m/s as it passes him on the way back down. How fast did Nicole throw the ball?

Homework Equations


Vf=Vi + at
y=Vi(t)+.5a(t)(^2)
Vf^2=Vi^2+2(a)(y)


The Attempt at a Solution


I've tried starting with the final V =0 and I've tried to solve the downward motion of the ball first, to attempt to get maybe the y value, or height of the ball at it's max. Please, where should I start? What am I missing?
 
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A hint, since no energy is lost - the speed going back down at a point is the same as the speed going up at that same height.
You just need v^2 = u^2 + 2as be careful of the signs!
 
Thanks mgb_phys! I finally got the correct answer of initial velocity=14 m/s.

for v^2 = u^2 + 2as; I let the -10 m/s of the downward velocity, u, = + 10 m/s at the same height of 5m on the upward velocity. I let v = unknown variable and the acceleration was equal to -9.8 m/s^2, and s=5m for the height. Thanks for the explanation!
 
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