Instantaneous rate of change of a sphere

AI Thread Summary
To find the instantaneous rate of change of the volume V of a sphere with respect to its radius r, the derivative of the volume formula V=4/3π(r^3) must be calculated. The derivative is dV/dr = 4πr^2. Evaluating this at r=5 micrometers gives a non-zero result, specifically 100π micrometers squared. The initial confusion stemmed from misunderstanding the nature of the derivative, which is not zero. Understanding the correct application of calculus is crucial for solving such problems.
ivysmerlin
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Homework Statement


Find the instantaneous rate of change of V with respect to r when r=5 micrometers


Homework Equations



V=4/3pi(r^3)

The Attempt at a Solution



would you just take the derivative? and if so, wouldn't it just be zero, because it comes out to be a real number, right? but that doesn't seem right...
 
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What is the derivative of V=4/3pi(r^3)? Now what would the value be at r=5micrometers? Not zero.
 
ooh, I am an idiot, thanks
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
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