Time-independent Schrödinger Equation

soul
Messages
61
Reaction score
0
Hi everyone,
I have been studying Quantum mechanics course for one month and our subject for now is Time-independent Schrödinger Equation. What I couldn't figure out is whether \Psi(x,\,0) = \Psi(x), since \Psi(x,\,0) doesn't contain any time dependence and \Psi(x) as well. Can someone explain me that that expression is true.
 
Physics news on Phys.org
your LaTeX isn't showing up for me... but it looks like you are asking whether psi(x,0) is equal to psi(x).

In which case, what do you mean by psi(x,0) and psi(x)?
 
I am new in quantum and there could be some lack of terminology in my question. I mean that Schr. Eq. at t = 0 which is shown as psi(x,0) and wave function independent of time psi(x) are the same in sqaure well and in some other cases??
 
In general, no. Consider a potential like the square well that has only bound-state solutions. Then there is a discrete set of allowed energies, the energy eigenvalues, E_n, and corresponding eigenfunctions, \psi_n(x), n=1,2,\ldots ; these are the solutions of the time-independent Schrodinger equation. Then, the most general solution of the time dependent Schrodinger equation is
\psi(x,t)=\sum_{n=1}^\infty c_n e^{-iE_nt/\hbar}\psi_n(x),
where the c_n's are arbitrary coefficients.

EDIT: something seems wrong with the TeX processing on the new server ...
 
to fix your LaTEX issues, you need to close with [/itex] or [/tex]...
 
Dr Transport said:
to fix your LaTEX issues, you need to close with [/itex] or [/tex]...
I did close with [/tex] and [/itex], but the slashes disappeared after uploading. This is a problem with the new server; see https://www.physicsforums.com/showthread.php?p=1922963
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top