What is the inverse of sinc(x) or sin(x)/x?

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Homework Statement



Does anyone know the inverse of sinc(x) or \frac{sin(x)}{x}?

Homework Equations



If sinc(x)=a, x=f(a). What is x in function of a?

The Attempt at a Solution



If I knew the exact value of a, I could find the corresponding value of x graphically. But how do I find x if I didn't know a?
 
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"sin(x)" itself does not have a true inverse. If you restrict x to between 0 and \pi, sin(x) and sinc(x) have inverses but the inverse of sinc(x) cannot be written in terms of simple functions. If y= sinc(x)= sin(x)/x, then finding the inverse function would be the same as solving xy= sin(x) for x which cannot be done in terms of simple functions.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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