Negative Feedback Example: Gain & Feedback Factor

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The discussion centers on an example of negative feedback in an amplifier circuit, illustrating how feedback affects gain. With an input signal of 101mV and an output of 10V, a feedback of 100mV is applied, resulting in a new input of 1mV. The gain without feedback is calculated as 10,000, while the gain with feedback drops to approximately 100. The confusion arises regarding the expected relationship between gains with and without feedback, as negative feedback reduces the input signal needed to maintain output. The explanation clarifies that negative feedback indeed subtracts from the input, aligning with the intended concept.
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While introducing negative feedback, my book gave the following example:

Let the signal voltage be 101mV and the output voltage of the amplifier be 10V
Out of this 10V a fraction (0.01) i.e. 100mV was made to feedback to the input circuit. The feedback circuit did not introduce any phase change. Hence, the feedback was negative (there is a 180 deg. phase reversal in amplifier circuit.)
The input signal now becomes (101-100) = 1mV

Then it was given that,
Gain (without feedback) is 10V/1mV = 10,000
Gain with feedback = 10V/101mV = 100 (approx)
Feedback factor = 100mV/10V = 0.01

My doubt is that shouldn't the gain without feedback and the gain with feedback be just the opposite?
With the feedback the input becomes 1mV and without feedback the input was 101mV
 
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They are keeping the output voltage constant and instead modifying the input signal. So with feedback, they needed a greater input signal to achieve the same output. This is to be expected with negative feedback since you are essentially subtracting off some of the output signal off from the input.
 
ohk... this was what was intended.
Thanks a lot Born2bwire
 
See complete derivation of op amp feedback and gain in thumbnail.
 

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