Calculating Shear Rate for Non-Newtonian Liquid Flow in Non-Circular Duct

  • Thread starter Thread starter delplace
  • Start date Start date
  • Tags Tags
    Liquid Newtonian
AI Thread Summary
Calculating the shear rate for shear-thinning liquids in non-circular ducts involves using rheological equations that relate shear stress to shear rate. The power law model, T = k * j^n, is commonly referenced, where T is shear stress, k is a consistency index, and n is the flow behavior index. To determine viscosity for calculating the Reynolds number, the apparent viscosity must be derived from the shear rate, which complicates the process in complex duct geometries. The main challenge is accurately calculating the shear rate (j) within the duct to find the viscosity needed for further calculations. Understanding these relationships is crucial for effective analysis of non-Newtonian fluid flow in engineering applications.
delplace
Messages
64
Reaction score
0
How to calculate the shear rate for the flow of a shear thinning liquid in a non circular duct
 
Physics news on Phys.org
With the constitutive equation relating viscosity (shear stress) to the shear rate. There are many models of shear thinning fluids; pick one.
 
Sorry Sir, I know for shear thinning fluids you have rheological equations linking share stress to shear rate. For example the power law model : T = k j^n. But when you have a shear thinning fluid flowing in a complex duct, you need a viscosity to calculate the Reynolds number. And to have the viscosity (apparent = T/j = kj^(n-1)) you need to calculat j in the duct ! It was the meening of my question. How to calculate the shear rate j ?
 
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
This has been discussed many times on PF, and will likely come up again, so the video might come handy. Previous threads: https://www.physicsforums.com/threads/is-a-treadmill-incline-just-a-marketing-gimmick.937725/ https://www.physicsforums.com/threads/work-done-running-on-an-inclined-treadmill.927825/ https://www.physicsforums.com/threads/how-do-we-calculate-the-energy-we-used-to-do-something.1052162/
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top