The static Killing vectors in Kruskal coordinates

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In the discussion on static Killing vectors in Kruskal coordinates, participants explore the implications of the Schwarzschild metric transformation. The key focus is on how the static Killing field vanishes at the point where both X and T equal zero, as indicated by the equation relating r and t. One participant suggests deriving explicit expressions for r and t from the provided equations to understand the behavior of the Killing vectors. Another emphasizes using the chain rule for partial derivatives to calculate the Killing vector field in Kruskal coordinates. The conversation highlights the complexity of transitioning between coordinate systems in general relativity and the mathematical intricacies involved.
Altabeh
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Hello

In the Kruskal extension of the Schwarzschild metric, where the metric is now transformed into the new coordinates (T,X,\theta,\phi), the line element is

ds^2=-\frac{32M^3e^{-r/2m} }{r}(-dT^2+dX^2)+r^2(d\theta^2+\sin^2(\theta)d\phi^2),

with

\left (r/2m-1 \right ) e^{r/2m}=X^2-T^2 (1)
and t/2m=2\tanh^{-1}(T/X). (2)

From the equation (1) we see that \nabla_{\alpha}r=0 at X=T=0 and this is obvious. Okay, but we know that the static Killing field \xi^{\alpha} becomes collinear with \nabla_{\alpha}r=0 thus requiring \xi^{\alpha} to also vanish there. My question is that how is this possible? Looking at the static Killing vectors of the Schwarzschild metric in a general Cartesian-like coordinate system x^{\mu},
\xi^0=0 and {\xi}^{i}={\epsilon}^{{ik}}{x}^{k}
where
\epsilon^{ik}=-\epsilon^{ki} =\left[ \begin {array}{ccc} 0&amp;a&amp;-b\\ \noalign{\medskip}-a&amp;0&amp;c<br /> \\ \noalign{\medskip}b&amp;-c&amp;0\end {array} \right],

with a,b,c being all arbitrary constants, how come the above requirement (X=T=0) gets all Killing vectors to vanish? My own view on the problem is that we must find the explicit expressions for r and t from (1) and (2), respectively, and then calculate the Killing vectors and put X=T=0. Am I on the right track or what?

Thanks in advance
 
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Sorry, I haven't tried to read your post in detail.

I would use (1) and (2), and the chain rule for ordinary partial derivatives to calculate the static Killing vector field in Kruskal coordinates.
 
George Jones said:
Sorry, I haven't tried to read your post in detail.

I would use (1) and (2), and the chain rule for ordinary partial derivatives to calculate the static Killing vector field in Kruskal coordinates.

Would you mind going a little bit deep into details of the calculation!?

Thanks
AB
 
In Schwarzschild coordinates, the static Killing vector is \partial/\partial t, and

<br /> \frac{\partial}{\partial t} = \frac{\partial T}{\partial t} \frac{\partial}{\partial T} + \frac{\partial X}{\partial t} \frac{\partial}{\partial X},<br />

so the components of Killing vector \partial/\partial t with respect to the \left\{ T, X, \theta, \phi \right\} coordinates are

<br /> \left\{ \frac{\partial T}{\partial t}, \frac{\partial X}{\partial t}, 0, 0 \right\}.<br />

Differentiating (1) and (2) with respect to t gives two linear equations in the two non-zero components.
 
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