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Homework Statement


The curve C has equation y=k x^3-x^2+x-5 where k is a constant.

A) Find the derivative of the function with respect to x

The point A with x-coordinate -\frac{1}{2} lies on C. The tangent to C at A is parallel to the line with equation 2 y-7 x+1=0 .

Find...

B) the value of k

C) the value of the y-coordinate at A.


Homework Equations



C is y=k x^3-x^2+x-5
Equation of the line parallel to the tangent of C at A ( -\frac{1}{2}) 2 y-7 x+1=0 .

The Attempt at a Solution



Ok, so I have found the derivative to be equal to: y'=3 k x^2-2 x+1

I am having trouble with the find y (and k) because if you were to solve that equation by substituting into it x we then have: \frac{1}{2} (7 x-1)=y=-2.25 but that y value isn't on the tangent line to C. So how would i go about completing these problems?

Thanks
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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