Finding radius of circle inscribed in a triangle

AI Thread Summary
To find the radius of the inscribed circle in a triangle given its side lengths, basic algebra and geometry can be applied, though the problem may require more advanced concepts. The discussion suggests that using circle theorems, particularly the relationship between tangents and radii, is essential. It raises the question of whether the problem becomes simpler if the triangle is a right triangle. The equality of tangents from two points on the triangle is also noted as a relevant theorem. Overall, the problem is solvable, but may involve a combination of geometric and trigonometric principles.
Bohrok
Messages
867
Reaction score
0

Homework Statement



Someone gave me this problem: finding the radius of the circle inscribed in the triangle with the given lengths.

28jzkn9.jpg


The Attempt at a Solution



The person asking about this problem said it was taken from a beginning algebra textbook. I tried figuring it out using just basic algebra, but I couldn't make any progress. Is this problem solvable with basic algebra/geometry? Would it be any easier if it were a right triangle?
 
Physics news on Phys.org
What I can deduce that you must use are some of the circle theorems, such as the angle made by a tangent and radius at the point of contact is 90°, as well as possibly some trigonometry.

I believe that the two tangents that meet (made by the 4 unit and 3 unit line) are both equal by one of the circle theorems.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top