Energy proportional to Amplitude squared?

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The energy of a wave is proportional to the amplitude squared due to the relationship between potential energy and maximum displacement in simple harmonic oscillators, where the potential energy is derived from the work done against an internal restoring force. This principle is illustrated mathematically using Hooke's Law, leading to the equation for potential energy. However, the same derivation does not directly apply to electromagnetic (EM) waves, as they lack a spring constant analogous to that in mechanical systems. Instead, the energy density of electric and magnetic fields in EM waves is proportional to the square of the electric field (E^2) and magnetic field (B^2), respectively. Textbooks often demonstrate this through examples involving capacitors and inductors, highlighting the fundamental differences between mechanical and electromagnetic wave energy.
SamRoss
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Does anyone know a simple derivation that explains why the energy of a wave is proportional to the amplitude squared?
 
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Does "simple" allow for calculus?

A wave is a collection of simple harmonic oscillators. The energy of a SHO equals the potential energy at maximum displacement. The PE at maximum displacement is the work done by an external force in pushing the oscillator out from the equilibrium position to maximum displacement. The external force acts against the oscillator's internal force which obeys Hooke's Law F = -kx.

\int_0^A {F(x)dx} = \int_0^A {kx dx} = \frac{1}{2} kA^2
 
Why doesn't this work for EM waves ?
 
vin300 said:
Why doesn't this work for EM waves ?

Why should it? What constant would you introduce in place of k, bearing in mind that it must have the same unit, and there isn't a spring constant for an EM wave.
 
jtbell said:
\int_0^A {F(x)dx} = \int_0^A {kx dx} = \frac{1}{2} kA^2

Thanks for the quick reply. I was actually thinking of an EM wave, though. Do you know a derivation for that as well?
 
In general, not just in EM waves, the energy density of an electric field E is proportional to E^2, and the energy density of a magnetic field B is proportional to B^2. Introductory textbooks usually derive these by considering the external work it takes to charge up a parallel-plate capacitor so that it has a field E between the plates:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capeng.html

or to increase the current flowing through a long solenoid (inductor) so it has a field B inside:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/indeng.html
 
cool, thanks
 

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