Inverse function and fourier series

zetafunction
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let be the Fourier expansion of the function

f(x) = \sum_{m=-\infty}^{m=\infty}c_{m} exp(imx)

valid on the interval (-1,1) , from this can we obtain the inverse function

f^{-1} (x) by reflection of the Fourier series through the line y=x ??
 
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can we obtain the inverse function f(-1)(x) by reflection of the Fourier series through the line y=x ??
Since exp(imx)=cos(mx)+i sin(mx), the function f(x) is complexe z=f(x)
Formally, the inverse function would not be f(-1)(x) but rather x=f(-1)(z)
What do you mean in writing "by reflection through the line y=x " ?
This would have a sens in case of reals y=f(x) and x=f(-1)(y). Presently it is not a real y, but a complex z instead of y.
What do you reflect through the line y=x ? Is it the curve representing y(x)= real part of z as a function of x ?, or is it the curve representing y(x)= imaginary part of z as a function of x ? or is it the curve representing y(x)= module of z as a function of x ? or is it the curve representing y(x)= argument of z as a function of x ?
 
assume function f(x) is real, then the Fourier series will include sines and cosines only .. but no exponential quantities.
 
assume function f(x) is real, then the Fourier series will include sines and cosines only .. but no exponential quantities
Sure ! if f(x) is assumed to be real the general terms of the Fourier series will be :
amcos(mx)+bmsin(mx) which is real.
But in the first question this was not the case : The general term was cmexp(i m x) = cm( cos(mx) + i sin(mx) ) which is not real.
So the question was raised in the general case of f(x) complex, even if the coefficients cm are complex (and/or real).
 
zetafunction said:
let be the Fourier expansion of the function

f(x) = \sum_{m=-\infty}^{m=\infty}c_{m} exp(imx)

valid on the interval (-1,1) , from this can we obtain the inverse function

f^{-1} (x) by reflection of the Fourier series through the line y=x ??

I'm interested in this as well if anyone has any ideas.
 
Well, the problem cannot be raised in terms of reflexion through the line y=x on a real space.
Seriously, expressing the reciprocal of a Fourier series is a very difficult problem, still open :
http://www.jstor.org/pss/2031811
http://www.jstor.org/pss/2034097
 
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