Is 11^n - 4^n a Multiple of 7? Proving with Mathematical Induction

Barbados_Slim
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Homework Statement


Prove that
<br /> 11^n - 4^n<br />
is a multiple of 7

Homework Equations


N/A

The Attempt at a Solution


I substituted k+1 in for n and simplified to get
<br /> 11(11^k)-4(4^k)<br />
but after this point I get stuck. Any help would be appreciated.
 
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Use that 11=7+4.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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