Finding an ellipse from a plane slicing a cone

Click For Summary

Homework Help Overview

The problem involves determining the parameters of an ellipse formed by slicing a right circular cone with a plane. The ellipse is described by the equation (x²)/a + (y²)/b = 1, with variables a and b needing to be expressed in terms of the height h and the angle φ of the plane. The original poster expresses uncertainty about how to approach the problem and relates it to the Dandelin spheres.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of Dandelin spheres to understand the relationship between the cone and the ellipse. The original poster questions how to derive the Dandelin spheres given the parameters of the cone and the plane. There is also exploration of the geometric relationships involving the semi-major and semi-minor axes of the ellipse.

Discussion Status

Some participants provide insights into the existence of Dandelin spheres and their relevance to proving the nature of the conic section. The original poster has made progress in understanding the minor axis but expresses doubts about the relationship between the angles involved in determining the major axis. There is acknowledgment of arithmetic errors in the calculations, but the discussion remains open-ended regarding the correct approach to find the major axis.

Contextual Notes

The original poster is working within the constraints of an independent study assignment and is seeking clarification on geometric relationships and assumptions related to the problem.

anomiet
Messages
4
Reaction score
0
Hello,

So I'm doing some independent study and I'm at a loss for this problem.

Homework Statement



Let's say we have an ellipse of the form (x2)/a + (y2)/b = 1 which we obtain by slicing a plane through a right circular cone with an opening angle of \theta (a fixed constant). We know the angle the plane makes with the xy-plane to be \phi. We also know the cut crosses the center line of the cone at height h. In terms of h and \phi, what is a and b?

Homework Equations



I found this page that seemed to be pointing me in the right direction, but I can't make much sense of it:

http://www.physicsinsights.org/conic_sections_1.html

Also, the equation of the ellipse they are using is related to the foci of the ellipse which I don't know how to relate to the equation of an ellipse I'm looking for.

The Attempt at a Solution



I'm honestly not sure where to start or if this is possible. It seems to me like it should be, so any help would be greatly appreciated.

Thank you,
-anomie
 
Physics news on Phys.org
Last edited by a moderator:
Thanks for the quick reply!

I'm imagining the process to get the major and minor radius of the ellipse would go something like this: Get the points of each sphere that touch the plane from above and below. This will be the foci of your ellipse, which in turn you can formulate the equation of the ellipse.

So how would I go about getting the Dandelin spheres with just the information in my above post? Essentially, how do I get the Dandelin spheres tangent to both a given plane and a given cone?

Thank you,
-anomie
 
hello anomie! :smile:

(just got up :zzz: …)
anomiet said:
So how would I go about getting the Dandelin spheres with just the information in my above post? Essentially, how do I get the Dandelin spheres tangent to both a given plane and a given cone?

you wouldn't bother … there obviously are such spheres (they're the largest possible inscribed spheres), and their mere existence proves that it is an ellipse (or parabola or hyperbola, depending on the slope)

once you know it is an ellipse, you know that the minor semi-axis, √b, is simply the radius of the cone at height h, and you can find the major semi-axis, √a, from the obvious triangle :wink:

(and you can find the foci using the usual formula)

btw, we usually write an ellipse with a and b squared … x2/a2 + y2/b2 = 1 … to make calculations easier!)
 
Ok, sweet, things are starting to make more sense. Thanks for the great help!:smile:

I was easily able to get the minor axis. As for the major axis, I'm not getting the right results. I tried using the right triangle that is formed on the ellipse with the sides being the semi-minor and semi-major axes. I determined that the angle formed with the hypotenuse and semi-major axis is always going to be half of opening angle (\theta/2). Thus, knowing the semi-minor axis, I can solve for a using a=b/(tan(\theta/2)). An image below to show what I mean:

rQviq.png


The thing that I'm not sure on is that the angle is indeed always half of the opening angle (which I'm really starting to doubt now). The other triangle I tried to use was the one formed by the center line of the cone, the semi-major axis, and the line formed by the edge of the cone. Yet, I still get vastly disproportional results.

Thank you,
-anomie
 
hi anomie! :smile:
anomiet said:
I determined that the angle formed with the hypotenuse and semi-major axis is always going to be half of opening angle … The thing that I'm not sure on is that the angle is indeed always half of the opening angle (which I'm really starting to doubt now).

no it isn't! :redface:
The other triangle I tried to use was the one formed by the center line of the cone, the semi-major axis, and the line formed by the edge of the cone.

that should do it …

what result did you get? :smile:
 
Hello!

So it looks like I was doing it right overall but just had some arithmetic errors I glanced over when it came to the finding the major axis. The math makes sense to me know thanks to you!:smile:

Thanks a lot for the help!

-anomie
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K