Positive Root Solutions for Quadratic Equations with Variable Coefficients

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The discussion centers on finding values of α for which the quadratic equation 4x² - 4(α-2)x + α - 2 = 0 has both roots positive. Key conditions include ensuring the discriminant D is non-negative, leading to α values in the intervals (-∞, 2] and [3, ∞), and requiring f(0) to be non-negative, which gives α > 2. The user also considers using the vertex formula -b/2a to confirm that the roots are positive. Ultimately, clarification on the equation's structure was provided, confirming the presence of a positive sign. The final answer for α remains to be determined based on these conditions.
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[SOLVED]

Homework Statement



Let4x^2-4(α-2)xα-2=0 (α\epsilon R)
be a quadratic equation, then find the value of α for which both the roots are positive.

Homework Equations


The Attempt at a Solution



the conditions will be
1) Discriminant D≥0
by this condition i got α (-∞,2][3,∞)
2) f(0) greater than or equal to 0
by this we get α (2,∞)

3) now should i use -b/2a(point exactly between both roots)
and equate as -b/2a greater than 0if-3rd point is right then what will be the final answer
α (?,?)union(?,?)
please provide help
 

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Sumedh said:

Homework Statement



Let4x^2-4(α-2)xα-2=0 (α\epsilon R)
be a quadratic equation, then find the value of α for which both the roots are positive.

Homework Equations





The Attempt at a Solution



the conditions will be
1) Discriminant D≥0
by this condition i got α (-∞,2][3,∞)
2) f(0) greater than or equal to 0
by this we get α (2,∞)

3) now should i use -b/2a(point exactly between both roots)
and equate as -b/2a greater than 0


if-3rd point is right then what will be the final answer
α (?,?)union(?,?)
please provide help


Are you sure the equation has typed up correctly? hopefully there should be a + or - sign between the x and the alpha??
 
Thanks,
I have solved the problem:smile:
there is a + sign.
 
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