Finding Concentration of a Standard Solution using % purity ?

AI Thread Summary
To find the concentration in ppm of a diluted Fe2+ solution, start with the initial mass of the Fe solution, which is 0.1964 g with a purity of 99.7%. The concentration of the original solution is calculated as 196.4 mg in 250 mL, resulting in 785.6 mg/L. After diluting 10 mL of this solution to 100 mL, the concentration is adjusted to 78.56 ppm, but this does not account for the purity. To find the correct ppm of Fe, multiply the concentration by the purity percentage, leading to a final concentration that reflects the actual amount of Fe present. Proper calculations should ensure the result aligns with the spectrometer's detection range.
nerdy_hottie
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Homework Statement



I need to know the concentration in ppm of a standard Fe2+ solution. (diluted)
Here is the data I have.
I have 0.1964 g of Fe solution
the purity is 99.7%

The original solution was the above # of g in 250ml water.
10ml of this was then pipetted into a 100ml volumetric flask and diluted.
I have to find the concentration in ppm of this diluted solution using the info from the starting solution.

Homework Equations



Don't think there are any. Just need logic to figure it out, of which I am limited in.

The Attempt at a Solution



196.4mg/0.250L
=785.6 mg/L
*(10ml/100ml)
=78.56 ppm

This is what I have, but I don't think it's right because 78.56 ppm is not in the range of the spectrometer we used. Also, I didn't use the 99.7% purity anywhere.

Thanks.
 
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nerdy_hottie said:

Homework Statement



I need to know the concentration in ppm of a standard Fe2+ solution. (diluted)
Here is the data I have.
I have 0.1964 g of Fe solution
the purity is 99.7%

The original solution was the above # of g in 250ml water.
10ml of this was then pipetted into a 100ml volumetric flask and diluted.
I have to find the concentration in ppm of this diluted solution using the info from the starting solution.

Homework Equations



Don't think there are any. Just need logic to figure it out, of which I am limited in.

The Attempt at a Solution



196.4mg/0.250L
=785.6 mg/L
*(10ml/100ml)
=78.56 ppm

This is what I have, but I don't think it's right because 78.56 ppm is not in the range of the spectrometer we used. Also, I didn't use the 99.7% purity anywhere.

Thanks.

Actually mg/ml is ppm - work it out.

Then you'll have the ppm of the stuff you put in the flask.

But only 99.7% of the stuff you put there is the Fe you are interested in.
So how many ppm is that?

Simples.

Assuming you have reported the question entirely because I am a bit puzzled about what ppm of "Fe" means, (you didn't weigh out iron filings, does your source give some convention?)
 
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