Dot Product: Understand When to Use Each Method

  • Thread starter Thread starter mindheavy
  • Start date Start date
  • Tags Tags
    Dot Vector
AI Thread Summary
The discussion clarifies the use of two methods for calculating the dot product of vectors. The first method, u·v = u_i·v_i + u_j·v_j, is applicable when the components of the vectors are known, allowing for straightforward calculation. The second method, u·v = |u|·|v|cosθ, is used when the magnitudes of the vectors and the angle between them are provided. It emphasizes that the choice of method depends on the available information and the desired outcome. Understanding these contexts aids in effectively applying the dot product in various scenarios.
mindheavy
Messages
62
Reaction score
0
I'm reading up on dot products and keep seeing two different examples.

One states that u\cdotv = u_{i}\cdotv_{i} + u_{j}\cdotv_{j}

Another: u\cdotv = |u|\cdot|v|cosθ

I'm not understanding when to use the first or second method?
 
Mathematics news on Phys.org
mindheavy said:
I'm reading up on dot products and keep seeing two different examples.

One states that u\cdotv = u_{i}\cdotv_{i} + u_{j}\cdotv_{j}

Another: u\cdotv = |u|\cdot|v|cosθ

I'm not understanding when to use the first or second method?
At the risk of stating something obvious, it depends on what information you are given and what you are trying to find. If you know the two vectors then you can find the dot product using the first equation. Then you can find the angle between the vectors using the second equation.

On the other hand, if you are given the lengths of the vectors and the angle between them, you can use the second equation to find the dot product.
 
Makes sense, I think the way the book I'm looking in words it was confusing me. Thanks
 
For example, if you are given that one vector is <1, 0, 0> and the other is <2, 2, 0> it is easy to calculate that the dot product is 1(2)+ 0(2)+ 0(0)= 2.

But if you are given that one angle has length 1, the other has length 2\sqrt{2}, and the angle between them is \pi/4, it is easiest to calculate (1)(2\sqrt{2})(cos(\pi&#039;4)= 2.

By the way, in spaces of dimension higher than 3, we can use the "sum of products of corresponding components" to find the dot product between two vectors, then use |u||v|cos(\theta) to define the "angle between to vectors".
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...

Similar threads

Replies
4
Views
3K
Replies
4
Views
3K
Replies
5
Views
2K
Replies
33
Views
4K
Replies
8
Views
2K
Replies
5
Views
2K
Replies
10
Views
3K
Back
Top