Calculate PSI of Hollow Cube with Hole Opened

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To calculate the psi of the hollow cube structure after the hole opens, Boyle's Law (PV=c) can be applied, considering the initial conditions of the cube. The cylinder, which is 14 cm long with a radius of 2 cm, will contain a vacuum after the air is released from the cube. This simplifies the calculations, as the cylinder does not need to account for atmospheric pressure. The change in volume and pressure can be determined using the initial psi of the cube and the volume of the cylinder. Understanding these principles allows for accurate pressure calculations in the modified structure.
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Suppose you have a hollow cube with a volume of 504c3. The inside of the cube has a psi of 94 and is just air. Now suppose that a hole opened in the bottom of this cube with an area of 12.56cm2 that leads to a hollow cylinder that is 14 cm long with a radius of 2cm. Now how would you go about calculating the psi of this whole structure after the hole is opened, the air is released and the volume has changed.
 
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Does the cylinder contain air at normal atmospheric pressure, or is it vacuum?
 
Nugatory said:
Does the cylinder contain air at normal atmospheric pressure, or is it vacuum?
The cylinder would have a vacuum inside it
 
daviddjh said:
The cylinder would have a vacuum inside it

OK - that makes it easy. Boyle's Law, ##PV=c## where ##c## is a constant, will get you an answer in short order.

(Boyle's Law would still get you there if the cylinder weren't a vacuum, but it would be more work).
 
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