Purpose of doing Legendre Transform

AI Thread Summary
The Legendre transform is used in thermodynamics to switch from internal energy (U) as a function of entropy (S) to Helmholtz free energy (F) as a function of temperature (T), facilitating calculations. The transform simplifies analysis by allowing the use of temperature, which is easier to measure than entropy. Although the resulting equation F = U - TS still contains entropy, it provides a more practical framework for understanding thermodynamic systems. This approach helps in deriving other important thermodynamic relationships and properties. Ultimately, the Legendre transform enhances the ability to work with thermodynamic variables effectively.
cainjm3
Messages
1
Reaction score
0
Hi, I'm new here, I was just wondering if anyone could help clarify a subject I'm having difficulties teaching myself... In thermo we perform a "Legendre transform" on the internal energy with respect to entropy. The stated purpose of this is so that we don't have to work in the entropy variable, since it is difficult to measure entropy. But the result of the transform (F = U - TS) still has entropy (S) in it. So how is this helpful? Thanks!
 
Physics news on Phys.org
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...
Back
Top