Homework Statement
Let ## a,b,c \in \mathbb{R}^{+} ##.
Prove that $$ \sqrt[3]{abc} \leq \frac{a+b+c}{3}. $$
Note: ## a,b,c ## can be expressed as ## a = r^3, b = s^3, c = t^3 ## for ## r,s,t > 0##.
Homework Equations
## P(a,b,c): a,b,c \in \mathbb{R}^{+} ##
## Q(a,b,c): \sqrt[3]{abc} \leq...