1 gram of C3H8 gas and 1 gram of O2 gas are delivered

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The discussion focuses on calculating the final pressure in a metal sphere after burning 1 gram of C3H8 and 1 gram of O2. The balanced reaction shows that C3H8 is the limiting reagent, leading to the complete consumption of reactants. After the reaction, the total moles of gas produced are calculated based on the stoichiometry of the reaction. With the known volume of 1 L and a temperature of 226.25 °C, the ideal gas law is applied to determine the final pressure in the sphere. The discussion emphasizes the importance of understanding limiting reagents and the ideal gas law in solving the problem.
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1. 1 gram of C3H8 gas and 1 gram of O2 gas are delivered to a metal sphere with a fixed volume of 1 L. After the two gases are introduced, the two reactants are ignited and burned according to the balanced reaction: C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(g)
After reaction, the sphere is held at 226.25 oC. What is the final pressure in the sphere given that all the compounds inside are gases and the limiting reagent is completely consumed with 100% yield ?




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1. Determine limiting reagent. Use the equation to find how much product there is and how much excess reagent.
2. Determine the total moles of gas, n, in the sphere.
3. Determine pressure in sphere. Since n, V, and T are known by this point, use ideal gas law.
 
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