1/R = 1/R1+ 1/R2 - Parallel Resistors

AI Thread Summary
The discussion focuses on calculating the equivalent resistance of resistors in parallel and series configurations. The formula 1/R = 1/R1 + 1/R2 is highlighted for determining the total resistance of parallel resistors. A specific example involving resistors in different rectangles is presented, indicating that the resistors in rectangle 3 are in parallel with those in rectangle 2, and this combination is in series with rectangle 1. The calculations lead to the conclusion that the equivalent resistance, RAB, equals 542 ohms. The discussion emphasizes the importance of correctly applying the formulas for resistor combinations to achieve accurate results.
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1/R = 1/R1+ 1/R2 - Parallel Resistors
3. I thought it was 1048 but that was just because I thought 542*2 I really had no idea how to work this
 
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Resistors in Rectabgle 3 are in parallel with that in rectangle 2 and the parallel combination are in series with rectangle 1:

http://img34.imageshack.us/img34/1774/67916352.png


RAB = [(R + RL) // R] + R = RL = 542

SO,

[(R + 542) * R / (R + R +542)] + R = 542
 
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