10^9 GeV dispersed collision energy

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The discussion revolves around understanding the concept of dispersed collision energy, specifically whether everyday objects like cars or trains can reach a total dispersed energy of 10^19 GeV. Participants explore the conversion of energy units from GeV to Joules, with calculations indicating that 10^19 GeV is equivalent to approximately 1.602 GJ. Examples are provided to illustrate this energy level, comparing it to the impact of large objects, such as a satellite falling from a height or the energy produced by a Boeing 737 crashing. The conversation highlights the challenges of conceptualizing such vast energy scales in familiar terms. Ultimately, the discussion seeks to relate high-energy physics to tangible real-world scenarios.
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When cars or trains collide.. does it exceed 10^19 for the total dispersed energy? I know that in particle accelerator you need to focus this much energy in the Planck scale to probe it. So I just want to know what is the equivalent everyday object that has this 10^19 GeV only its not focused at small area but dispersed (so useless as particle accelerator).

It is often asked what's it's like to have 13 TeV collision at the LHC.. like what bigger object has similar dispersed collision energy. So I want to know what bigger object has at least 10^19 GeV dispersed collision energy.
 
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jtlz said:
When cars or trains collide.. does it exceed 10^19 for the total dispersed energy? I know that in particle accelerator you need to focus this much energy in the Planck scale to probe it. So I just want to know what is the equivalent everyday object that has this 10^19 GeV only its not focused at small area but dispersed (so useless as particle accelerator).

It is often asked what's it's like to have 13 TeV collision at the LHC.. like what bigger object has similar dispersed collision energy. So I want to know what bigger object has at least 10^19 GeV dispersed collision energy.
Do you know how to convert units of energy from eV to Joules? Using the SI system of units, you can calculate the KE of a train in Joules, which will go to zero in a collision. Use Google to find the mass of a typical heavy train. Or even of a fully-loaded container ship. Please show us your calculations so we can check them. Thanks! :smile:
 
berkeman said:
Do you know how to convert units of energy from eV to Joules? Using the SI system of units, you can calculate the KE of a train in Joules, which will go to zero in a collision. Use Google to find the mass of a typical heavy train. Or even of a fully-loaded container ship. Please show us your calculations so we can check them. Thanks! :smile:

I can't find any converter of GeV to Joules... most of them have only eV to Joules.. and I don't want to keep typing too many zeros... so I was asking if anyone knows roughly from reading books of what's Planck scale energy is like compared to everyday objects...
 
jtlz said:
I can't find any converter of GeV to Joules... most of them have only eV to Joules.. and I don't want to keep typing too many zeros... so I was asking if anyone knows roughly from reading books of what's Planck scale energy is like compared to everyday objects...
What does the letter "G" stand for as a prefix for a number?
 
berkeman said:
What does the letter "G" stand for as a prefix for a number?

Ok i'll attempt manual convertion since I can't find a converter for this.

1 GeV = 1 billion eV or 1 x 10^9 eV

1J = 6.241509⋅10^18 eV

so 1J = 6.241509⋅10^18 eV * (1 GeV /10^9 eV) = 6.241509 x 10^9 GeV

so the Planck energy 10^19 GeV x (1J / 6.24 x 10^9 GeV) = 1.6 x 10^10 Joule

how big is 1.6 X 10^10 Joule? equivalent to a tornado or hurricane plucking a tree or lifting cars? what?
 
jtlz said:
Ok i'll attempt manual convertion since I can't find a converter for this.

1 GeV = 1 billion eV or 1 x 10^9 eV

1J = 6.241509⋅10^18 eV

so 1J = 6.241509⋅10^18 eV * (1 GeV /10^9 eV) = 6.241509 x 10^9 GeV

so the Planck energy 10^19 GeV x (1J / 6.24 x 10^9 GeV) = 1.6 x 10^10 Joule

how big is 1.6 X 10^10 Joule? equivalent to a tornado or hurricane plucking a tree or lifting cars? what?

I'm trying out some online calculator site about mass, velocity and kinetic energy in joules... https://www.calculatorsoup.com/calculators/physics/kinetic.php

I entered the mass and energy to come up with the kinetic energy near 1.6 x 10^10 Joules...

I entered mass of 30,000 kilograms and velocity of 1000 meters /second..

really? you need that much weight and speed to reach Planck energy? Or is there some mistakes somewhere?
 
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When an electron moves through 1 volt in an electric field, it changes energy by 1 eV.
Energy = Q * V. The charge on the electron; Qe = 1.60217653e-19 coulomb.
Therefore; 1 eV = 1.60217653e-19 coulomb * 1 volt = 1.60217653e-19 joule. So 1 joule = 6.241e+18 eV

The 13 TeV at the LHC = 13.0e12 * 1.602e-19 = 2.08 uJ

Potential Energy = m∙g∙h; where g = 9.8 m/s/s on Earth.
If you drop a 1.02 kg brick on your foot, from a height of 1 metre, it delivers energy of;
1.02 kg * 9.8 m/s/s * 1 m = 10 joule.

That is 10 / 2.08e-6 = 5 million times as much as an electron from the LHC.

Your 10^19 GeV = 1e28 eV = 1e28 * 1.602e-19 joule = 1.602 GJ
If a satellite weighing 1020 kg fell on you from 100 km above it would deliver a pain equivalent of;
1020 * 9.8 * 100e3 = 1 GJ
 
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Guys.. what is the formula relating energy to distant scale.. for example. 1 GeV.. 1 TeV, 5 TeV.. etc. with the relevant scales.. for example 10^19 GeV related to Planck scale.. how about say 10^12 GeV. How do you compute the distant scale for this?
 
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There is the inverse square law that gives the energy per square metre of a radiating wavefront.
For a single photon, 1/r2 gives the probability of being hit, since photons maintain their energy until they hit something.
 
  • #11
Baluncore said:
There is the inverse square law that gives the energy per square metre of a radiating wavefront.
For a single photon, 1/r2 gives the probability of being hit, since photons maintain their energy until they hit something.

What is the formula that involves the energy...

In particle accelerator such as the LHC... what is the smallest distance the 1.5 TeV particle energy can probe? (noting that the 13 TeV is for the collision energy of the entire accelerating protons.. so each individual particle would have less energy than that.. so it's about 1.5 TeV maximum now)..

So given particle energy = 1.5 TeV..
what is the distance scale (in meters it can probe).. what's the exact formula?
 
  • #12
jtlz said:
So given particle energy = 1.5 TeV..
what is the distance scale (in meters it can probe).. what's the exact formula?
Sorry that I seem to just be feeding you wiki pages, but see the table here: https://en.m.wikipedia.org/wiki/Electronvolt
 
  • #13
Baluncore said:
When an electron moves through 1 volt in an electric field, it changes energy by 1 eV.
Energy = Q * V. The charge on the electron; Qe = 1.60217653e-19 coulomb.
Therefore; 1 eV = 1.60217653e-19 coulomb * 1 volt = 1.60217653e-19 joule. So 1 joule = 6.241e+18 eV

The 13 TeV at the LHC = 13.0e12 * 1.602e-19 = 2.08 uJ

Potential Energy = m∙g∙h; where g = 9.8 m/s/s on Earth.
If you drop a 1.02 kg brick on your foot, from a height of 1 metre, it delivers energy of;
1.02 kg * 9.8 m/s/s * 1 m = 10 joule.

That is 10 / 2.08e-6 = 5 million times as much as an electron from the LHC.

Your 10^19 GeV = 1e28 eV = 1e28 * 1.602e-19 joule = 1.602 GJ
If a satellite weighing 1020 kg fell on you from 100 km above it would deliver a pain equivalent of;
1020 * 9.8 * 100e3 = 1 GJ

Can you think of a more everyday example of what 1.602 GJ can do? What examples do particle physicists use to illustrate what it's like to probe Planck scale with particle accelerator... like imagine 2 trains colliding and all the energy were focused on the Planck scale? but trains come in different masses.. perhaps a bus colliding.. or better yet. what examples were exactly used by physicists to illustrate the large Planck scale energy?
 
  • #14
jtlz said:
Can you think of a more everyday example of what 1.602 GJ can do?
If you turned on a 2.645 kW electric heater, then kept it going for one whole week, it would transfer 1.6 GJ.

Energy flow; 1 joule per second = 1 watt.
Electrical energy is sold by the; unit = 1 kW∙Hour = 1k * 60 min * 60 sec = 3.6 MJ
If one unit costs you $0.20, then $1.00 will get you 18 MJ.
So 1.6 GW would add $88.89 to your electricity bill.
 
  • #15
Let's compute some figures...

formula of Kinetic Energy = 1/2 m * v^2 (this is also used for momentum of a particle?)
given velocity = 250 meters / second (average speed of airliner)
and Kinetic Energy of =1.6 GJ
the mass needs to be 51,200 kilograms (approx. weight of a Boeing 737 I checked in the weights of airliner lists)

therefore to get Planck energy is like having a Boeing 737 flying at 250 meters/second...

but then would it still be right to say that to get probe Planck scale is like having Boeing 737 flying at 250 meters/second crashing into a building and the energy focusing into the Planck scale?
 
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