...
F = I LxB where L and B are vectors and where the x represent a vector multiplication. B is the magnetic field and L the length of the projectile in which the current pass. Finally I is the current in amp.
You can also calculate the energy given to the projectile by this force :
Ek = F * D (D is the distance on which we apply the force)
Then you can calculate the speed of the projectile by isolating the speed in the formula :
Ek = 1/2 m*V^2 (Where v is the speed and m the weight of the projectile)
However it is important to consider that a huge amount of energy is lost with friction.
Also you can find Ek by simply consider that it is equal to the energy of the capacitors. Once again only a fraction of this energy is transferred to the projectile. In fact, for a rail gun made by student with a small budget the fraction can be of 1-3 %....
Hey guys! I wish you the best of luck on this project, as I am currently working on the same exact thing! I'm building a railgun as my senior project, and I am a senior Aerospace engineering undergrad at Cal Poly (come to Cal Poly, and do Aero if you want to do AWESOME CRAP). Anyways. Ditch the idea of making your own capacitors. Sorry guys. Keep going to/get a summer job and save up around $500. You build one of these guys that works, posts a youtube video and make a website talking about your efforts (you may get some donations!), and you can do whatever you like with your life. You will officially be awesome.
About the quote above...the Forcing is wrong on the projectile. The force is calculated as
F = I*IvXB
I = the MAGNITUDE of the current running through the rails/projectile
Iv = the vector DIRECTION of the current running through the projectile
B = the vector DIRECTION of the magnetic field caused by the current running through each parallel rail. Its important that you have pretty near-perfect parallel rails, or you will get side forces that can do some serious damage. [CAREFUL ON THIS PROJECT...]
*Sam Barros page talks about this...
Thats the basic way that you want to do it, but not the easy way to calculate your forces. Your next question should be...how do we find B?? NOT EASILY. B is brought about by the inductance of the rails per meter (permeability).
Read about inductance here: http://en.wikipedia.org/wiki/Permeability_(electromagnetism)"
Read about permeability here: http://en.wikipedia.org/wiki/Permeability_(electromagnetism)"
After all that reading you do...here's a nice formula for the estimation of the force on the projectile:
F = 0.5 * L' * I^2
L' = being the permeability (or inductance per meter) of the rails TOGETHER!
I = current through the rails
A pretty good forum talking about his very topic:
https://www.physicsforums.com/showthread.php?t=323052"
For more on how to find L', google inductance per meter of railguns. There are a lot of professional papers out there on it, and it is not a simple topic AT ALL. (were currently working on that as well)
Here's a good place to start and see how hard it really is:
http://ieeexplore.ieee.org/xpl/freeabs_all.jsp?arnumber=559966"
Capacitors that you want to look into: electrolytic, oil-filled (maybe), or flash.
Ratings on capacitors you should worry about:
- Voltage rating - the voltage at which that single capacitor can be charged
- Capacitance - the bigger the better. You will want something around 10-1000 uF for a low budget gun. I'm going slightly larger budget and will most likely be paying well over $500 just for the capacitors.
- Current...is hard to find a rating for overall current through capacitors. Ripple current is a rating on a capacitor, but most of them are less than 35A, and your homemade capacitor did better than that. So when you get capacitors you can either try and analyze the heat generated by the internal resistance of the capacitors and see if it reaches the melting point of the capacitor materials...or just build it and hope they don't break...
If you want to read up on someone else that 'fiddled around' and made a rail gun, look at Sam Barros' site(s) and read everything. Extremely informative, and he may help you with questions you may have if you email him. Don't take my word for it, and if you're reading this Sam, don't hate me.
http://www.powerlabs.org/railgun2.htm"
Guys, this is a big project and should be well-documented and NOT taken lightly. To get any kind of force in the projectile you must have upwards of or more than 100,000Amps of current and at least between 450V to 1000V of voltage. That is plenty of power to kill you where you stand, and anyone else that happens to be touching you at the same time (up to 10-15 people in series

). I can't reiterate this enough BE CAREFUL and GET AN ADULT to help. Find your quirky neighborhood physics teacher or washed-up engineer doing software and get him on board! This is not safe for you to do on your own, you will kill yourself. At these voltages, you can be thrown across a room merely by voltage alone, if it doesn't just kill you. BE CAREFUL
If you have any questions I will be very happy to answer them. You can contact me through this forum, or you can email me at
jeffmaniglia@gmail.com