Exploring 2D Diffraction Spacing and Light Transmittance in 40um x 40um Lattice

[strokebow]

2D Aperture/Diffraction Spacing

Hi,

I have a 2D square spacing of 40um x 40um lattice. I am passing light through the spacing.

I want to know how much of the light gets through... the transmittance.

Clearly the light is being blocked by the surrounding lattice wires and the rest of the light passes through the 40um x 40um opening. Hence, I am calculating it as the area of lattice divided by the total area.

Is this correct?

Also, it would be interesting to know how the light diffracts as it moves through this 2d opening. And how the size of the square opening affects the amount of light that is diffracted. Anyone know what this is?

cheeers

 

[eljose79]

Hello,

I can confirm that your calculation for transmittance is correct. The transmittance can be calculated as the area of the opening divided by the total area, assuming the light is passing through a uniform medium.

Regarding diffraction, the size of the square opening does affect the amount of light that is diffracted. This is due to the phenomenon of diffraction, where light waves passing through small openings or around obstacles spread out and interfere with each other, creating a pattern of light and dark regions. The size of the opening determines the spacing between these light and dark regions, with smaller openings resulting in larger spacing and more diffraction.

In the case of your 2D aperture, the diffraction pattern would be a 2D version of the familiar single-slit diffraction pattern. The exact pattern would depend on the wavelength of the light, the size and shape of the aperture, and the distance between the aperture and the screen where the pattern is observed.

I hope this helps answer your questions. Let me know if you have any further inquiries.