2nd Kirchhoff's law for all passive elements

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The discussion focuses on applying Kirchhoff's Second Law to a circuit involving inductors, capacitors, and a current source. It emphasizes that the sum of voltages around a loop must equal zero, expressed as VI + VR + VL + VC = 0, and remains valid even with time-dependent voltages. When a voltage source is added in series, the equation adjusts to VI + VR + VL + VC = VV, or alternatively, VI + VR + VL + VC - VV = 0, depending on the orientation of the voltage source. Participants highlight the importance of consistently marking diagrams to determine whether voltages support or oppose current flow. The conversation underscores the necessity of careful analysis in circuit equations to account for potential discrepancies in voltage signs.
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How would be the 2nd Kirchhoff's law for this circuit here:

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I'm asking because I don't know how is the behavior of the inductor, capacitor and current source wrt the 2nd Kirchhoff's law...
 

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Kirchhoff's 2nd law states that the sum of the voltages around a loop is zero. It also applies to inductors and capacitors so..

VI + VR + VL + VC = 0

The voltage (particularly on Inductors and capacitors) is time dependant but the above still applies at any instant in time.
 
CWatters said:
Kirchhoff's 2nd law states that the sum of the voltages around a loop is zero. It also applies to inductors and capacitors so..

VI + VR + VL + VC = 0

The voltage (particularly on Inductors and capacitors) is time dependant but the above still applies at any instant in time.

And if I add a voltage source in series in this circuit, the equation will be so:

VI + VR + VL + VC = VV

Yeah!?
 
Jhenrique said:
And if I add a voltage source in series in this circuit, the equation will be so:

VI + VR + VL + VC = VV

Yeah!?

Yeah!
 
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Yes. Although it might be better to write it as..

VI + VR + VL + VC - VV = 0

Did you realize you may have implied a different orientation for the additional voltage source VV?
 

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or if you prefer
 

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CWatters said:
Yes. Although it might be better to write it as..

VI + VR + VL + VC - VV = 0

Did you realize you may have implied a different orientation for the additional voltage source VV?

CWatters said:
or if you prefer

Interesting and confused!
 
But I don't think so... I place in the left side of the equation the potential difference that favors the circulation of the current and I place in the right side the potential differences opposes the circulation of the current. I can't think in another way more intuitive...
 
It's not always obvious if a "voltage" opposes or increases the current. Best practice is to mark your diagram in a consistent way, then go around each loop summing all the voltages. Then solve any simultaneous equations (eg for circuits with multiple loops). You may well find some unknown voltages turn out -ve when you were expecting them to be +ve.
 
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