Six, 6.6kV ,3phase, alternators are connected to a common set of bus bars. Each has positive negative and zero sequence reactances of 0.90 ohm, 0.72 ohm, 0.30 ohms respectively . An earth fault occurs on one bus bar . Determine the value of fault current if all alternator neutrals are solidly grounded. HINT: Fault Current,I =3V/(Z0+Z1+Z2) for single generator when single Line to ground fault occurs. where, V is the Phase voltage (i.e. ( 6.6kV / 1.732 = 3.8106 kV )) Can anyone help me on how to solve this problem. Please.