Consider 3D geometric algebra. Let all points on a line be given by the parametrization x=tu+y, in which the parameter runs from minus infinity to plus infinity. a. Show that for all points on the line we have x(wedge)u=y(wedge)u. b. Show that the vector d pointing from the origin onto a point on the line, such that d has the shortest length, satisfies d. u=0. c. Show no that this vector d is given by d=(y(wedge)u)(u)^(-1). d. Given two lines given by parametrizations s u1+y1 and r u2+y2, where the parameters s and r run from minus to plus infinity. Show that for the two lines to have an intersection we must have that (y1-y2)(wedge)(u1-u2) is proportional to u1)(wedge)(u2. I posted this because i wanted help first plotting the parametrization and i figured ill be asking questions about the rest of it later, thus i typed out the whole problem. I realize this plotting is hard to explain on an internet thread, but maybe some tips?