4-letter words can be made from pulleys?

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The discussion revolves around calculating the number of 4-letter words that can be formed from the letters in "PULLEYS." Two cases are considered: one with all different letters and another with two L's and two other letters. The initial calculation suggests a total of 480 possible combinations, but there is disagreement regarding its correctness. A participant suggests that the correct method involves considering arrangements and repetitions, leading to a different conclusion of 35 combinations. The conversation highlights confusion over the application of combinatorial principles and the need for clarification from the teacher.
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Hi, could someone please verify my answer? Thanks.. :smile:


How many 4-letter words can be made from the letters of the word PULLEYS? Explain your answer.

There are two mutually exclusive cases by which four letter-word can be arranged from the word PULLEYS. Let n(A) be the number of arrangements of 4-letter word with all different letters. Let n(B) be the number of arrangements that contain two L's and two other letters.

Case A:
There are C(6, 4) ways to choose subsets of four different letters. Each of these subsets has the length of four and can generate 4! sequences of letters. Therefore, n(A) = C(6, 4) x 4! = 360.

Case B:
There are C(2, 2) X C(5, 2) subsets that contain two L's and two other letters. The letters in each subset can be arranged in: C(4, 2) X C(2, 1) X C(1,1) different ways. Therefore, n(B) = C(2, 2) X C(5, 2) X C(4, 2) X C(2, 1) X C(1,1) = C(5, 2) X 4!/2! = 120

Therefore, the total number of four-letter words: n(A) + n(B) = 480
 
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This is the correct answer as I see it .
 
arunbg: that's what i thought also, but my teacher said that it's wrong.. Any idea why?
 
what's ur teacher's answer ?
 
arunbg: My teacher said that it is wrong but she did not tell what is her answer. So i sent her an e-mail asking what is the correct answer, but she hasn't got back to me. And unfortunately, e-mail is the only available form of communication since this course is an online course.

Can I ask anyone else's opinion for this question?

Thank you...
 
ok, I think you should try this:
C=n! / r! (n-r)!
where n is the nuber of symbols, taken r at the time.
therefore, in this case, n=7 and r=4
C= 7! / 4!3! and that's how you get 35 different combinations.
 
Tinaaa said:
ok, I think you should try this:
C=n! / r! (n-r)!
where n is the nuber of symbols, taken r at the time.
therefore, in this case, n=7 and r=4
C= 7! / 4!3! and that's how you get 35 different combinations.

Welcome to PF Tinaaa.
Don't want to start on a sour note, but you might want to reread the question .
 
I've just reread it and I still think that there is nothing wrong with my answer. 35 4-letter words can be formed from the word PULLEYS =) Why do u think it's wrong??
 
Well, firstly you haven't taken into account the no. of ways in which you can arrange the letters to form different words.
Also, you have not taken into account the repitition of the two L's in
PULLEYS which of course cannot be interchanged to get new words.
7C4 only gives you the no of ways of choosing 4 different objects from 7.

I suggest you read the OP's detailed solution to see how it is done.

Regards
Arun
 
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