Solving y(4)-4y" = 16e2x: Need Help!

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I'm working on this equation and I think I remember how to do it, but my notes from this class are so scattered and I can't seem to find the section in my textbook.

the problem is:

y(4)-4y" = 16e2x

can someone help me out with just getting started? Doesn't it have something to do with letting w=y" and w"=y4?
 
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You need to get the homogeneous solution and the particular solution.
To obtain the homogeneous solution use the characteristic equation.
 

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