5 blocks connected together on an incline

  • Thread starter Thread starter loxo
  • Start date Start date
  • Tags Tags
    Blocks Incline
AI Thread Summary
The problem involves five connected blocks, with two on an incline at angle θ, and seeks to determine the acceleration of the last block not on the incline. The relevant equations include F = ma and the gravitational force on the incline, F(grav) = mg sin(θ). The user attempted to analyze the forces separately for the blocks on and off the incline, providing a diagram for clarity. There is uncertainty regarding the direction of the tension force (F_t) affecting the first three blocks. The discussion highlights the need for careful consideration of force directions in multi-block systems.
loxo
Messages
1
Reaction score
0

Homework Statement


Five blocks are connected together, each with mass m. Two of the five blocks are on an incline of angle θ. What is the acceleration of the last block that is not on the incline. See attached diagram for further details.


Homework Equations



F = ma
F(grav) = mg sin(θ) (on an incline)

The Attempt at a Solution



Broke the componets down in 2 separate parts of those on incline and those off. Attached diagram with details. Not sure if my solution is correct.
 

Attachments

Physics news on Phys.org
The result is correct, but I think F_t should point in the opposite direction for blocks 1-3.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top