5 count bag of balloons, 6 color possibilities

  • Thread starter Thread starter cad08cad08
  • Start date Start date
  • Tags Tags
    Color Count
cad08cad08
Messages
2
Reaction score
0
We have a standard assortment of balloons which is 6 different colors. We also have a 5 count bag of balloons which uses this standard assortment. Obviously you can get all 6 colors in a 5 count bag but my colleagues were curious about the other distributions.

The chances of only getting one color is pretty straight forward 1 out of 6^4 or 1 out of 1,296 bags will only have one color. Likewise getting 5 different colors is easy to figure out (1 * 5/6 *4/6 * 3/6 * 2/6) 120 out of 1,296 bags. My question to you is the other possibilities...2, 3, and 4 colors? Does this involve Stirling numbers?

1 color = 1/1,296
2 colors = ?
3 colors = ?
4 colors = ?
5 colors = 120/1,296

Thanks!
 
Physics news on Phys.org
cad08cad08 said:
... Obviously you can get all 6 colors in a 5 count bag

Hm ... maybe YOU can but I don't see how.
 
Helpful, thanks.
 
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Back
Top