Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

555 Timer RC Charging Capacitor Conundrum

  1. Apr 17, 2009 #1
    Hello. I am currently trying to evaluate just how much power the external RC circuitry of a 555 timer uses over 1 cycle. Whilst the capacitor is charging the current falls exponentially. Naturally the voltage also falls through the resistors but this is couteracted by the rise in voltage of the capacitor as it charges. Basically what im trying to find out is whether there is a way to get an average current reading between 1/3Vcc and 2/3Vcc using the equation
    (4.5/101000 ⋅ e^(- x/0.4747)

    (4.5 = Vcc)
    (101000 is the total resistance in Ohms)
    (0.4747 is the RC time constant)

    Would the median value suffice?
  2. jcsd
  3. Apr 17, 2009 #2
    [tex]P=fC \Delta V^2[/tex]
  4. Apr 17, 2009 #3
    I dont mean to sound dense or anything but ive never tried this stuff before. The way I read your answer is:

    Power = Frequency x Capacitance x Change in Voltage Squared

    Is this right? And if so how does this tie in the the duty cycle?
  5. Apr 17, 2009 #4
    LTSpice (and probably other simulation programs) have the NE555 in its library. Try it.
  6. Apr 17, 2009 #5
    Right. The power disipated in charging and discharging the capacitor is independent of the duty cycle.

    The current, at any time t, is obtained from constructing a piecewise continuous function from

    [tex]v(t) = v_i \left( 1 - exp(-t/RC) \right)[/tex]
    [tex]v(t) = v_f \left( exp(-t/RC) \right)[/tex]
    [tex]i(t) = C \frac{dv}{dt} .[/tex]

    You might be better off using the average,

    [tex]\overline{I} = C \frac{\Delta V}{\Delta T} .[/tex]
    Last edited: Apr 17, 2009
  7. Apr 23, 2009 #6
    It is useful to review the astable NE555 circuit at http://www.daycounter.com/Calculators/NE555-Calculator.phtml
    Scroll down to circuit model at bottom of page.The capacitor charges through the series resistance RA plus RB, but the charging time fraction (duty cycle) of charging time depends on the ratio (RA + RB)/(RA + 2 RB), so the average current depends on the ratio of RA/RB). Furthermore, although the frequency remains constant for given values of RA, RB, ad C, the average current increases linearly with the applied voltage VP.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook