Derivation of the thermodynamic potentials using Legendre transformations

AI Thread Summary
The discussion focuses on the derivation of thermodynamic potentials using Legendre transformations, specifically how to systematically generate the enthalpy (H), Helmholtz function (F), and Gibbs function (G) from the internal energy (U). It begins with the differential form of internal energy, dU = TdS - pdV, and demonstrates the process of transforming variables to derive the potentials. The transformation involves manipulating the equations to express U + pV as enthalpy, and subsequently deriving the Helmholtz and Gibbs functions by changing the natural variables. There is some confusion about the necessity of Legendre transformations in this process, with participants questioning whether they are indeed being applied. The thread highlights the importance of understanding these transformations in the context of thermodynamics.
Andromon
Messages
3
Reaction score
0
Hello guys, I'm studying Thermodynamics and I don't totally see how you introduce the potencials using Legendre transformations.

I have seen a non formal explanation showing how you can interpret them, but not a rigorous demonstration of how you get them via the Legendre transformations.

Do you know any site or book that covers it?

Also all the other issues, like the Maxwell transformations and the Euler equations and relations.

Ty.
 
Physics news on Phys.org
I expect I'm not giving you a full picture of what a Legendre transformation is, but here's a systematic way to generate potentials, H, F and G...

Start with dU = TdS- pdV.

From the product rule: dU = TdS- {d(pV) - Vdp}

We can write this as: d{U + pV} = TdS + Vdp

U + pV is usually designated as H. It is the enthalpy potential. Its 'natural variables' are S and P.

We can product-transform TdS instead of pdV, and obtain the Helmholtz function U - TS, with natural variables T and V.

Finally we can transform both TdS and pdV,obtaining the Gibbs function G = U + pVTS, with natural variables p and T.
 
Ok, I see it, is an add and subtract trick, but I don't see where there it's used the Legendre transformation, it's not needed at all?
 
I'd be surprised to be told that I wasn't actually doing Legendre transformations in my earlier post, but let wiser heads decide.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top