nhrock3
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8)
U=\{x=(x_{1},x_{2},x_{3},x_{4})\in R^{4}|x_{1}+x_{2}+x_{4}=0\}
is a subspace of R^{4}
v=(2,0,0,1)\in R^{4}
find u_{0}\in U so ||u_{0}-v||<||u-v||
how i tried:
U=sp\{(-1,1,0,0),(-1,0,0,1),(0,0,1,0)\}
i know that the only u_{0} for which this innequality will work
is if it will be the orthogonal projection on U parallel to v
i am not sure about the theory of finding it
what to do next?
U=\{x=(x_{1},x_{2},x_{3},x_{4})\in R^{4}|x_{1}+x_{2}+x_{4}=0\}
is a subspace of R^{4}
v=(2,0,0,1)\in R^{4}
find u_{0}\in U so ||u_{0}-v||<||u-v||
how i tried:
U=sp\{(-1,1,0,0),(-1,0,0,1),(0,0,1,0)\}
i know that the only u_{0} for which this innequality will work
is if it will be the orthogonal projection on U parallel to v
i am not sure about the theory of finding it
what to do next?
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