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Here's a counterexample to that statement:I disagree with [itex]1^{+\infty}[/itex] is indeterminate.

If my initial equations are correct then [itex]1^{+\infty}[/itex] is bounded by e, 1/e.

lim

_{n→∞ }[(1+10^{-n})^{2·10n}] = e^{2}Replace the "2" with larger numbers, and it's evident that 1

^{∞}is not only indeterminant but unbounded as well.