A 1.2 kg block is pushed under water and held there. What is the buoyant force?

AI Thread Summary
The buoyant force acting on a submerged 1.2 kg block is calculated using the weight of the water displaced, which is determined by the equation w = mg. The correct answer is 11.76 N, derived from multiplying the mass of the block by the acceleration due to gravity (1.2 kg x 9.8 m/s²). It is clarified that if the buoyant force equaled the weight of the block, it would float instead of needing to be pushed underwater. The discussion emphasizes that the buoyant force corresponds to the density of water multiplied by the volume of the block. Understanding this concept resolves any confusion regarding buoyancy and displacement.
kuhatelyn
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A 1.2 kg block is pushed beneath the water and held there. What is the buoyant force
(in N) acting on the block?
(a) not enough information to answer
(b) 11.76
(c) 1.2
(d) 14.56
(e) none of these

Since buoyant force is equal to the wt of the water displaced, I used the equation w=mg
w=1.2 x (9.8)
so I got 11.76 as my answer.
Is this right?
 
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If the bouyant force were equal to the weight, mg, it would not be necessary to push the block under water- it would float at whatever depth you placed it. The bouyant force is equal to weight of water displaced. The bouyant force is, as you say, the weight of the water displaced- and that will be equal to the density of water times the volume of the block.
 
Thank you! It makes sense now
 
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