- #1

- 81

- 0

**[SOLVED] A box of mass 8.0kg is being dragged along the ground by a force of 30N.**

## Homework Statement

A box of mass [tex]8.0kg[/tex] is being dragged along the ground by a force of [tex]30N[/tex].

(a) If the friction force is [tex]26N[/tex] what is the resulting acceleration?

(b) If the frictional force is one-quarter of the normal reaction force, what is the acceleration?

## Homework Equations

F = m.a

## The Attempt at a Solution

(a) [tex]m = 8.0kg \ , \ F = 30N[/tex]

[tex]F = 30 - 26 = 4N[/tex]

[tex]F = m.a[/tex]

[tex]a = \frac{F}{m} = \frac{4}{8} = 0.5ms^{-2}[/tex]

(b) [tex]m = 8.0kg , \ , F = 30 \times \frac{3}{4} = 22.5N[/tex]

[tex]a = \frac{F}{m} = \frac{22.5}{8.0} = 2.8ms^{-2}[/tex]

Are any answers correct?