A concept from calculus that has always bothered me

  • Thread starter Thread starter ronaldor9
  • Start date Start date
  • Tags Tags
    Calculus Concept
ronaldor9
Messages
91
Reaction score
1
When one writes \int p(t) \, dt is the constant of integration implied? I have always thought that it wasn't necessary to write \int p(t) \, dt +k. However, in my diff. eq. book the constant is ussually written out, why is this so?

In addition the book also writes \int_{t_o}^t p(t) \, dt +k isn't the constant here unnecessary since we now have the limits of integration included?
 
Physics news on Phys.org
It's usually written because it's definite.

Suppose

<br /> y &#039; = f(x, y(x)) \ , y(x_0) = y_0<br />

It does seem logical to say that (assuming f is integratable)

<br /> \int y&#039; dx = \int f(x,y(x)) dx \rightarrow y = \int f(x,y(x)) dx + k<br />

but since we have initial conditions, we can do better.

<br /> <br /> \int_{x_0}^{x} y&#039;(t) dt = \int_{x_0}^{x} f(t,y(t)) dt \rightarrow y - y_0 = \int_{x_0}^{x} f(t,y(t)) dt<br />
Thus,
<br /> y = \int_{x_0}^{x} f(t,y(t)) dt + y_0<br />

Better?
 
Last edited:
Thanks l'Hopital
Why is the later form preferred over the first form?
 
Simply because it actually involves the initial conditions.
 
There is one part in my book where it writes R&#039;(y)=Q(x_0,y)
and then by integration R(y)=\int_{y_0}^y Q(x_0,y)\,dy.

Shouldn't theauthor here have included a constant at the end of the integral as you have written in you example?
 
ronaldor9 said:
There is one part in my book where it writes R&#039;(y)=Q(x_0,y)
and then by integration R(y)=\int_{y_0}^y Q(x_0,y)\,dy.

Shouldn't theauthor here have included a constant at the end of the integral as you have written in you example?
Yes, because with that notation R(y0)= 0 which is not true for all anti-derivatives. I would also object to using "y" both as a limit of integration (and so outside the integral) and as the variable of integration. Much better would be either
R(y)= \int_{y_0}^y Q(x_0,t)dt+ C
or
R(y)= \int^y Q(x_0, t)dt
where we don't need the "C" because the lower limit of integration is left open.

If you write just
R(y)= \int Q(x_0,y)dy
the usual notation for the "anti-derivative", the constant C is implied. You do not write it there. Of course, if you wrote
R(y)= \int y^2 dy= \frac{1}{3}y^2+ C
The constant on the right is necessary.
 

Similar threads

Replies
1
Views
1K
Replies
15
Views
2K
Replies
1
Views
2K
Replies
9
Views
2K
Replies
2
Views
2K
Back
Top