MHB A Density Problem and a Mass Problem

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To solve the first problem regarding the gold coin, the volume can be calculated using the formula v = m/d, but it's crucial to convert the mass from grams to kilograms for consistent units. The density of gold is given as 19300 kg/m3, so the calculation should be v = 9.25 x 10^-3 kg / 19300 kg/m3. In the second problem about the helium balloon, the mass of helium also requires consistent units; the density should be converted to kg/m3 or the volume to cm3. Both problems highlight the importance of unit consistency in calculations for accurate results.
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Hoping you can give input. I need you to show work and explain. Here is what we have:1. A gold coin has a mass of 9.25 grams. What is its volume if the density of gold is 19300 kg/m3?

v= m/d

v= m 9.25 g/d 19300kg/m3

Not sure how and what to do...please help2. A helium filled balloon has a volume of 4.5 m3. What mass of helium does it hold if the density of helium is 1.8x 10-4 g/cm3?

v=4.5 m3
d=1.8x10-4g/cm3
m=dxv

m= 1.8x10-4g/cm3x4.5m3

100cm/1m
m3/m=m2

100cm/1mx100cm/1mx100cm/1m

1000000

m=1.8x10-4 gx4.5 x100x100x100

1.8 x100x100x100

1.000008
180 x 4.5= 810
m=810 (My answer, is this correct?)
 
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On problem 1, you have the right idea, but you have mixed units: grams versus kilograms. Make sure you have consistent units! So your computation should be
$$V=\frac{m}{\rho}=\frac{9.25\times 10^{-3}\;\text{kg}}{1.93\times 10^{4}\;\text{kg/m}^{3}}=\dots$$
The same exact issue plagues your second problem. You must get consistent units! Either convert your volume to cubic centimeters, or convert your density to kilograms per cubic meter.
 
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