A doubt respect to the sign of the torsor (torque)

[Queren Suriano]

Homework Statement

Actually I have two doubs, the first one is Why in the solution of this problem, in the sumatory of moments in C, Force 2=10?? If in the sumatory of moments in F, Force 2 is 416.7 N. Actually I calculate with 416.7 N, and T in C = 100 N. The other doubt is with the sign of the torsor along the axis CD. Because the action-reaction law, the torsor in the axis will enter in the axis, thus it will NEGATIVE, but the solution takes positive!. Why??

Homework Equations

The Attempt at a Solution

It is in the The problem statement, at the picture

 

[phinds]

I can't answer your questions but I would point out to you that as far as I can tell, you don't have any doubts at all, what you have is questions.

https://www.physicsforums.com/showthread.php?t=607274

 

[Queren Suriano]

I can't answer your questions but I would point out to you that as far as I can tell, you don't have any doubts at all, what you have is questions.

https://www.physicsforums.com/showthread.php?t=607274

Ok, thank you for correcting my grammar. It's true, I have 2 questions

 

[berkeman]

I understood what you meant by "doubt"...

You are saying that the book's solution shows F2 = 10N? That seems way off...

And as for the direction of the net torque on the center gear, I think you have labeled the direction incorrectly. The force F2 on the bottom of the gear is larger, so the net torque will be towards the back of the apparatus (clockwise as seen from the front)...

 

[Queren Suriano]

I understood what you meant by "doubt"...

You are saying that the book's solution shows F2 = 10N? That seems way off...

And as for the direction of the net torque on the center gear, I think you have labeled the direction incorrectly. The force F2 on the bottom of the gear is larger, so the net torque will be towards the back of the apparatus (clockwise as seen from the front)...

Thank you