Output power (torque-rotation) equivalent inertia

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SUMMARY

This discussion focuses on calculating the equivalent moment of inertia in a drive train system while associating output power with input torque. The key equations utilized include T = I*ω, P = T*ω, and the expression for equivalent inertia Ieq = I1 + I2*(r1/r2) + T2*α1/(α2)². The conversation emphasizes the importance of correctly applying angular acceleration (α) instead of angular velocity (ω) in the context of torque calculations. The participants aim to simplify the expression by eliminating angular acceleration from the final term.

PREREQUISITES
  • Understanding of rotational dynamics and torque calculations
  • Familiarity with the concepts of moment of inertia and angular acceleration
  • Knowledge of power equations in mechanical systems
  • Basic proficiency in algebraic manipulation of equations
NEXT STEPS
  • Research the relationship between torque and angular acceleration in mechanical systems
  • Study the derivation of equivalent inertia in multi-shaft systems
  • Explore advanced applications of the kinetic energy equation EK = (I*ω²)/2
  • Learn about the implications of rotational dynamics in engineering design
USEFUL FOR

Mechanical engineers, physics students, and professionals involved in the design and analysis of drive train systems will benefit from this discussion.

Adriano Marcato
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Homework Statement



A lot of people are familiar with equivalent inertia problems, where you have a drive train and inertia on different axis and you calculate the equivalent inertia on whichever shaft you want. This time I (try to) bring something new, trying to associate the output power to the equivalent moment of inertia on the input.

The system and the known information are shown bellow. Let's assume T1 is the driving torque and we want to get an equivalent inertia of the shafts AND the output torque T2
upload_2017-6-23_9-56-31.png

Homework Equations


T = I*ω
EK = (I*ω2)/2
P=T*ω
ω2*r1 = ω2*r2

The Attempt at a Solution


By means of equivalent kinetic energy, I've come to the following expression:
Ieq = I1 + I2*r1/r2 + T21/(ω2)2
I've been trying to eliminate the rotational speed in the last term.
 
Physics news on Phys.org
Torque = I*alpha {angular accel} not I*ω {angluar velocity}
 
Oh! indeed, I am sorry for the mistake. I meant to include a point above.
Please consider
Formula: T = I*α
Attempt at solution: Ieq = I1 + I2*r1/r2 + T21/(α2)2
Try to cancel the alphas on the last term.
 

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