A follow up of the question about gears of the winder

  • Thread starter Thread starter stephen
  • Start date Start date
  • Tags Tags
    Gears
AI Thread Summary
The discussion focuses on the mechanics of a winder's gear system, clarifying that the worm gears are not glued and rotate at different rates. The user seeks to understand the calibration of the counter's label, noting that it appears unusual to use increments of 1000 instead of simpler numbers. They realize the winder records rotations based on the 30 teeth gear, not the handle's turns, leading to confusion about counting revolutions. Additionally, the orientation of the worm gears is discussed, highlighting that the angled teeth design allows for better contact and reduced pressure. Overall, the user gains a clearer understanding of the gear mechanism but still has questions about the gear orientation.
stephen
Messages
16
Reaction score
0
Hi all!
I open a new thread since I am going to post another picture, and this would overload the old thread.

The first picture shows the number of teeth of the meshing gears.
I was wrong that the pair of worm gears are glued. They are not glued as mentioned by Q_Goest. And the two gears are rotating at different rates.

The second picture shows the label of the counter.

What I am going to ask is the meaning of the label.

From the number of teeth of the gears indicated in the first picture, it is known that the 102 worm gear rotate at a lower speed than the 100 one.
I find that for every 30 turns of gear A would finally cause Gear C(102teeth) to lag behind GearC(100teeth) by 1/51 turns.

So in the label, it can be visualised that when the 30 turns are rotated, the outer point would just finished rotating one complete circle. And the inner pointer would move one little grid. (Some error in the picture drawn, the inner circle should be divided into 51 divisons, instead of 50 divisions. I find this in the real label provided.)

First of all, is my intepretation correct?

If yes, I have got some questions.

Why do the calibration of the inner circle so strange? Why don't it just writes "10, 20, 30, 40, 51" but "1000, 2000, 3000, 4000, 5100" instead?


Second, if I am the user of the this winder, and I am going to count how many revolution of have I rotated the handle. If I am to do so, I need to multipy the readings of 30, right? Don't you think this is strange? Have I interpreted the usage wrongly?

And it seems to me that the outer circle is of no practical use...It only returns to zero for every 30 times of rotation of the handle.

Sorry for such a long thread...I am really such an idiot. Hope to receive your nice help~
 

Attachments

  • winderf.JPG
    winderf.JPG
    33.5 KB · Views: 549
  • counter mark ff.JPG
    counter mark ff.JPG
    39.8 KB · Views: 584
Engineering news on Phys.org
oops..
I just knew that I could post pictures in the 'reply'..
sorry for starting another thread...
Please relocate this thread if any inconvenience is caused.
 
I discovered that I asked a silly question.
The winder is not going to record how many turns the handle retotate but the 30 teeth gear...So the label should really be marked "1000, 2000, 3000, 4000.etc"
I think I now understand the entire mechanism.

But I still don't quite understand the orientation of the pair of worm gears. i.e. the "turbine" shape...
Q_Geost, do you mean the pair of grears' orientation is such that the drive gear would have a greater contact area with the pair of worm gear? And this reduce the pressure?
 
Each time gear B rotates, the worm gear rotates once and the two gears it is rotating (the 100 tooth and 102 tooth worm wheels) only rotate by 1 tooth. Also, gear B will rotate 100/30 or 3.333 times for each time you rotate the handle. This assumes there is only an idler gear between the two which isn't certain given the picture.

Regarding the "turbine" look of those two gears, I'm assuming you're referring to the slighty slanted angle on the teeth. There's a couple of pictures of typical worm gear and worm wheel assemblies here:
http://www.qtcgears.com/e-store/Images/Worm.jpg
http://www.tasonic.com.tw/images/PAGE6/6-2.JPG
In each case you can see the teeth on the worm wheel are slightly angled so they mesh with the worm gear (screw shaped gear). Is that what you were referring to? If so, the reason for the slight angle on the teeth should be fairly obvious. It allows the worm gear and worm wheels to contact over a larger area.
 
Last edited by a moderator:
I need some assistance with calculating hp requirements for moving a load. - The 4000lb load is resting on ball bearing rails so friction is effectively zero and will be covered by my added power contingencies. Load: 4000lbs Distance to travel: 10 meters. Time to Travel: 7.5 seconds Need to accelerate the load from a stop to a nominal speed then decelerate coming to a stop. My power delivery method will be a gearmotor driving a gear rack. - I suspect the pinion gear to be about 3-4in in...
How did you find PF?: Via Google search Hi, I have a vessel I 3D printed to investigate single bubble rise. The vessel has a 4 mm gap separated by acrylic panels. This is essentially my viewing chamber where I can record the bubble motion. The vessel is open to atmosphere. The bubble generation mechanism is composed of a syringe pump and glass capillary tube (Internal Diameter of 0.45 mm). I connect a 1/4” air line hose from the syringe to the capillary The bubble is formed at the tip...
Thread 'Calculate minimum RPM to self-balance a CMG on two legs'
Here is a photo of a rough drawing of my apparatus that I have built many times and works. I would like to have a formula to give me the RPM necessary for the gyroscope to balance itself on the two legs (screws). I asked Claude to give me a formula and it gave me the following: Let me calculate the required RPM foreffective stabilization. I'll use the principles of gyroscopicprecession and the moment of inertia. First, let's calculate the keyparameters: 1. Moment of inertia of...
Back
Top